Azron's solution to Varr's Puzzle #1 [SPOILER]

[Azron]

k. First things first with this puzzle is to look at what we know:

1) There are 16 coins that need to flipped
2) There must be a total of 18 flips (6x3)
3) Any one coin must be flipped an odd number of times

These 3 things tell us that one coin must be flipped 3 times, the remaining 15 to be flipped once (if more than one coin was flipped 3 times, there would be fewer flips than coins remaining).

Now, knowing every coin bar one can only be flipped once tells us that the coin that needs to be flipped 3 times must be on one of the main diagonals, and since the problem has rotation symmetry of order 4 we can concentrate on the leading diagonal alone.

If we number the coins thus:

01 - 02 - 03 - 04
05 - 06 - 07 - 08
09 - 10 - 11 - 12
13 - 14 - 15 - 16

Then taking the 01 as our coin to be flipped three times (being the first in the lead diagonal), we flip the following sets:

01, 02, 03
01, 06, 11
01, 05, 09

Which means coins 1, 2, 3, 5, 6, 9 and 11 are flipped. We then perform the moves:

07, 10, 13
04, 08, 12
14, 15, 16

Which flips the remaining coins as required.

Obviously this solution has slight variations (it can be rotated and performed in a different order, also, the way the last 9 coins to be flipped are arranged into 3-coin groups can be changed slightly).

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Nice puzzle, had me slightly baffled to begin with, but once I applied a bit of mathematically inspired logic it came out '>

[Yip]

I must say that I loved your use of math in solving this puzzle.